is this correct ? 5.(5 points) A 0.10-mal sample of a diprotic acid, H2A, is dissolved...
A 5.00 g quantity of a diprotic acid (H2A) was dissolved in water and made up to exactly 250 mL. Calculate the molar mass (in g/mol) of the acid if 25.0 mL of this solution reuired 11.1 mL of 1.00 M KOH for neutralization.
A sample of oxalic acid (a diprotic acid of the formula H2C2O4) is dissolved in enough water to make 1.00 L of solution. A 100.0 mL sample of this solution is titrated with a solution of sodium hydroxide of concentration 0.750 M and requires 20.0 mL of sodium hydroxide to reach the end point. Calculate the mass of the original oxalic acid sample.
For the diprotic weak acid H2A, Ka1 = 2.7 × 10-5 and Ka2 = 5.2 × 10-7. What is the pH of a 0.0550 M solution of H2A? What are the equilibrium concentrations of H2A and A2– in this solution?
For the diprotic weak acid H2A, Ka1 = 3.1 × 10-5 and Ka2 = 8.2 × 10-7. What is the pH of a 0.0650 M solution of H2A? What are the equilibrium concentrations of H2A and A2– in this solution?
A student titrated a 25.00-mL sample of a solution containing an unknown weak, diprotic acid (H2A) with NaOH. If the titration required 17.73 mL of 0.1036 M NaOH to completely neutralize the acid, calculate the concentration (in M) of the weak acid in the sample. (a) 9.184 x 10‒4 M (b) 3.674 x 10‒2 M (c) 7.304 x 10‒2 M (d) 7.347 x 10‒2 M (e) 1.469 x 10‒1 M
Consider the titration of 100.0 mL of the weak diprotic acid H2A (0.10 M) with 0.20 M NaOH. What are the major species at each of the following points in the titration? (Water is always assumed to be a major species.) 1. Before any NaOH is added 2. After 25.0 mL of 0.20 M NaOH is added 3. After 50.0 mL of 0.20 M NaOH is added 4. After 75.0 mL of 0.20 M NaOH is added 5. After 200.0...
22.0-mL sample of 0.122 M diprotic acid (H2A) solution is titrated with 0.1016 M KOH. The acid ionization constants for the acid are Ka1=5.2×10−5 and Ka2=3.4×10−10. A. At what added volume of base does the first equivalence point occur? ____ mL B. At what added volume of base does the second equivalence point occur? _____ mL 12
A diprotic acid, H2A,H2A, has acid dissociation constants of ?a1=4.15×10−4Ka1=4.15×10−4 and ?a2=3.73×10−12.Ka2=3.73×10−12. Calculate the pH and molar concentrations of H2A,H2A, HA−,HA−, and A2−A2− at equilibrium for each of the solutions. A 0.176 M0.176 M solution of H2A.H2A. pH = [H2A]=[H2A]= MM [HA−]=[HA−]= MM [A2−]=[A2−]= MM A 0.176 M0.176 M solution of NaHA.NaHA. pH= [H2A]=[H2A]= MM [HA−]=[HA−]= MM [A2−]=[A2−]= MM A 0.176 M0.176 M solution of Na2A.Na2A. pH= [H2A]=[H2A]= MM [HA−]=[HA−]= MM [A2−]=[A2−]= M
Diprotic acid (H2A), Part II (Homework) Homework. Unanswered For carbonic acid, Kail = 4,5 x 10-7. What is the (HCO3-) in a 0.10 M carbonic acid solution? Respond with the correct number of significant figures in scientific notation (Use E notation and only 1 digit before decimale.g, 2.5E5 for 2.5 x 10" Numeric Answer: Unanswered * Submit Diprotic Acid (H2A), Part 1 (Homework) Homework . Unanswered For carbonic acid, Kal = 4.5x 10-7. What is the pH of a 0.10...
A diprotic acid, H2A, has acid dissociation constants of Kai = 3.52 x 10-4 and Ka2 = 2.03 × 10-11 . Calculate the pH and molar concentrations of H2A, HA, and A2- at equilibrium for each of the solutions. A 0.206 M solution of H,A. pH = H2A] HA1 A 0.206 M solution of NaHA pH- [H2A] = [HA-] = A 0.206 M solution of Na,A. pH- [H2A] EA T [A21