10) How many grams of ice do I need to add to the 356 grams of...

Question

Question

10)

How many grams of ice do I need to add to the 356 grams of my soda if I wish to lower the temperature of my soda from 21.8°C to 3.9°C. Assume that the specific heat of the soda is 4.172 J/g⋅C°. The specific heat of water is 4.184 J/g⋅C°. The heat capacity of the glass is 56.4 J/C°. The molar enthalpy of fusion (melting) of ice is 6.018 kJ/mol.

Answer 1

Answer #1

As we can see from the question that the equilibrium temperature es 3.9°c. Temp. or soda decreases and ice firest melts than

Answer 2

Similar Homework Help Questions

Calculate the heat required in Joules to convert 18.0 grams of water ice at a temperature...

Calculate the heat required in Joules to convert 18.0 grams of water ice at a temperature of -20° C to liquid water at the normal boiling point of water. Given: -specific heat of ice = 2.09 J/g°C -specific heat of liquid water = 4.184 J/g°C -specific heat of water vapor = 2.03 J/g°C -molar heat of fusion of water = 6.02 kJ/mol -molar heat of vaporization of water = 40.7 kJ/mol
You add 100.0 g of water at 51.0 °C to 100.0 g of ice at 0.00...

You add 100.0 g of water at 51.0 °C to 100.0 g of ice at 0.00 °C. Some of the ice melts and cools the water to 0.00 °C. When the ice and water mixture reaches thermal equilibrium at 0 °C, how much ice has melted? (The specific heat capacity of liquid water is 4.184 J/g · K. The enthalpy of fusion of ice at 0 °C is 333 J/g.) Mass of ice = References Use the References to access...
How much heat is released when 105 g of steam at 100.0°C is cooled to ice...

How much heat is released when 105 g of steam at 100.0°C is cooled to ice at -15.0°C? The enthalpy of vaporization of water is 40.67 kJ/mol, the enthalpy of fusion for water is 6.01 kJ/mol, the molar heat capacity of liquid water is 75.4 J/(mol • °C), and the molar heat capacity of ice is 36.4 J/(mol • °C). A)347 kJ B)54.8 kJ C)319 kJ D)273 kJ

You order a 16 oz glass of tea (where the mass of water is 474 grams)...

You order a 16 oz glass of tea (where the mass of water is 474 grams) from a local restaurant. The tea is freshly brewed and has an initial temperature of 28.93 °C. You add ice to cool it. If the heat of fusion of ice is 6.020 kJ/mol and each ice cube contains exactly 1 mol of water (assume the ice does not add anymore volume), how many ice cubes are necessary to cool the tea to 1.54 °C?...
An ice cube with a mass of 46.4 g at 0.0 ∘C is added to a...

An ice cube with a mass of 46.4 g at 0.0 ∘C is added to a glass containing 4.20×102 g of water at 45.0 ∘C . Determine the final temperature of the system at equilibrium. The specific heat capacity of water, ?s , is 4.184 J/g⋅∘C , and the standard enthalpy of fusion, Δ?∘fus , of water is 6.01×103 J/mol . Assume that no energy is transferred to or from the surroundings.
An ice cube with a mass of 53.0 g at 0.0 °C is added to a...

An ice cube with a mass of 53.0 g at 0.0 °C is added to a glass containing 368 g of water at 45.0 °C. Determine the final temperature of the system at equilibrium. The specific heat capacity of water, Cs, is 4.184 J/g·°C and the standard enthalpy of fusion, ΔH°fus, of water is 6.01 × 103 J/mol. Assume that no energy is transferred to or from the surroundings.

You order a 16 oz glass of tea (where the mass of water is 474 grams)...

You order a 16 oz glass of tea (where the mass of water is 474 grams) from a local restaurant. The tea is freshly brewed and has an initial temperature of 25.43 Â°C. You add ice to cool it. If the heat of fusion of ice is 6.020 kJ/mol and each ice cube contains exactly 1 mol of water, how many ice cubes are necessary to cool the tea to 2.83 Â°C? The specific heat of the "tea" is 4.184...
You order a 16 oz glass of tea (where the mass of water is 474 grams)...

You order a 16 oz glass of tea (where the mass of water is 474 grams) from a local restaurant. The tea is freshly brewed and has an initial temperature of 20.39 Â°C. You add ice to cool it. If the heat of fusion of ice is 6.020 kJ/mol and each ice cube contains exactly 1 mol of water, how many ice cubes are necessary to cool the tea to 2.62 Â°C? The specific heat of the "tea" is 4.184...
You order a 16 oz glass of tea (where the mass of water is 474 grams)...

You order a 16 oz glass of tea (where the mass of water is 474 grams) from a local restaurant. The tea is freshly brewed and has an initial temperature of 20.73 °C. You add ice to cool it. If the heat of fusion of ice is 6.020 kJ/mol and each ice cube contains exactly 1 mol of water (assume the ice does not add anymore volume), how many ice cubes are necessary to cool the tea to 0.240 °C?...

The answer is 13626 J. However, I kept getting an answer around the 14,000 range. Please...

The answer is 13626 J. However, I kept getting an answer around the 14,000 range. Please show all of your work in this problem and how you will reach the final answer of 13626 J. Calculate the heat required in Joules to convert 18.0 grams of water ice at a temperature of -20° C to liquid water at the normal boiling point of water. Given: -specific heat of ice = 2.09 J/g°C -specific heat of liquid water = 4.184 J/g°C...