Extra Credit Question (5 points): 1. Derive the Henderson-Hasselbach equation for weak acids. I have given...
I need to know the % output when : weak acid( pKa=6) is in pH of urine at 6 and pH or urine at 8. Also the weak base (pKa 7) in pH of urine at 6 and pH or urine at 8. Effect of urine pH on delivery route: Weak organic acids and bases can reach the luminal fluid (the filtrate, the primary urine) either by glomerular filtration in Bowman's capsule or by secretion in the proximal tubule. In...
please help walk me through how to solve these, the questions change everytime. i am not even sure where to start. thank you HON WILL UNULNEM TULENERAL CHEMISTRY LABE Amber Gloria's Qula History Lab & Quiz Exploring Buffers Background Incorrect Question 3 0/1 pts If you mix a weak acid and a weak base together with concentrations of 0.33 and the acid has apk, -8.58, what is the pH of the buffer? Give your answer to two decimals. pH =...
pH of 9.2 using ammonium nitrate: pKa= 9.24 2 Introduiction The Henderson-Hasselbalch equation, or A-1 HAl relates the pH of a buffer with the pKo of the acid and the concentration of the conjugate base A- and the monoprotic acid HA. In cq. (1), pH-_ log[H+], pK, =-log Ka, and [J]i and [JIe are the initial and equilibrium molar concentration of the Jth species, respectively. The buffering capacity of the buffer is given by [1] Ka H+ where K,e-1.0 ×...
I am not sure how to approach this question I think I have the correct answer for number 1 but I am not exactly sure how to apply it to number 2 if number 1 is correct. 1. What is the best range of buffering that is provided when a weak acid is present in a water solution? the best range of buffering that is provided when a weak acid is present in a water solution is a pH of...
please solve 4 of them, thank you. 2. Buffer Questions (Do 4 of 5 problems---6 pts each) a. Three different weak bases and their Kh values are listed below in a table. Which one would be best to form a buffer with a pH of 8.50? Explain why, and numerical calculations are expected as part of your answer to receive full credit. K = K,K) = 1.0 x 10-14 Weak Base K, Value KPK ammonia (1,8 x 10 hydrazine 1.3...
Question two A buffer solution is able to maintain a constant pH when small amounts of acid or base are added to the buffer. Consider what happens when 1 mL of a 5 M solution is added or 0.005 mol of HCl are added to a 100.0 ml solution acetic acid buffer that contains 0.0100 mol of Acetic acid, HC,H,O,, and 0.0100 mol of sodium acetate, NaC,H,O2. The initial concentration of both the acid and the base are 0.0100 mol/0.1000...
Question 1) (3 Points) Consider the strong form below. Derive the weak form equation. The space used is W H-1,1]. Define the spaces Wp and Wo Dirichlet Strong Form: Find u e W2,00 such that u"(x) _ 2 sin(x)a(z) u(-1)-1 u(1) 1 cos(x), for any x ? ?-[-1,1]
Question 1 1. Using an equation like equation 3, derive the expression for k given in equation 4. 2. What solvent mixture are you using in parts A-C? In part D? Whoat effect will the different solvent system used in part D have on the rate of reaction? Explain. 3. Given the Arrhenius equation (Equation 5) and the brief discussion of it below, how will you actually calculate Eact? In other words, show the equation you will use. (Eact ???)...
(Set 2) Practice Problems in Equilibrium All weak acids use this generic equation: HA(aq)+ H2O() A (aq) + H30*(aq) And all weak bases use this one: B(aq)+ H2O(I) = BH*(aq)+ OH'(aq) Part A: Finding K, or Kb 3.012? What is the value of Ka for a weak acid if a 1.44 M solution has a pH 1. 2. A weak acid is 0.00987 M, but is found to be 25.5 % ionized. What is the pH? 3. The pH for...
A buffer solution is able to maintain a constant pH when small amounts of acid or base are added to the buffer. Consider what happens when 1 mL of a 5 M solution is added or 0.005 mol of HCl are added to a 100.0 mL solution acetic acid buffer that contains 0.0100 mol of Acetic acid, HC,H,O,, and 0.0100 mol of sodium acetate, NaC,H,O,. The initial concentration of both the acid and the base are 0.0100 mol/ 0.1000 L...