Question

Joe and Susie want to preform a titration using 1.75M phosphoric acid and sodium hydroxide. What mass of sodium hydroxide would be needed to neutralize 37mL of the phosphoric acid sol

Answer 1

H3PO4 (aq) + NaOH lag! Na H₂ Por caq) + H₂O(l) Molarity = moles of solute - Volume of solution (ind) 4 Concentration of H₂ POA, [Hapo] = 1.75 M . And, Volume of H₂ por solution = 37 me d's, moles of Hapon = 1.75 x 37 x 10-3 For neutralization to occur , moles of H₂ POq lacid) = moles of NaOH (base) or,moles of Naol = 1.75 x 37 x 10-3 Las moles mass And Mw (NaOH) = 40 g/mol molas-mass (Mo) Hence, mass of NaOH = 1.7537x10-3 x 40 g § 2.590