Question

For the following reaction, 60.9 grams of bromine are allowed to react with 30.8 grams of chlorine gas. bromine (g) + chlorine (g) —bromine monochloride (g) What is the maximum amount of bromine monochloride that can be formed? grams What is the FORMULA for the limiting reagent? What amount of the excess reagent remains after the reaction is complete? grams Submit Answer

Answer 1

2 Bill Reaction Br. (g) + 4 (q) Ammount oo.gg 30.89 moles Goog 3018 159.808 70.906 7.38 Mol 0.43 Mol dividing by ... sachants Coufticien 0:38 0:43 minimum (limiting) Therefore moles of product UBY = 0.38X2 = 0.7 mol ammount = 0.76 mol x 15-36 g/mol =87.679 limiting Reagent = Brz Romanina reagent = (0.43-0.38) = 0.05mol x 70.906 Remaining reagens = 3.549