Question

325 mL of a 0.0700M solution of sodium hydroxide reacts with 75,0 mL of a 0.115 M solution of cobalt(III) sulfate. What mass (in g) of cobalt(III) hydroxide( MM = 109.96) is formed assuming the reaction went to completion? NaOH(aq) + CO2(SO4)3(aq) --> Na2SO4(aq) + C(OH)3(s) (unbalanced) Write answer to three significant figures. (8 00:40:48 Numeric Response

Answer 1

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# Balanced chemical equation ; 6 Na H(aq) + Co, (cos (99) 3 Ng, Se, 4) & Co (oh),G) Moles of NaOH available for exu = molarity x volume in Citses = 0.0700M X 0.3252 = 0.02275 mol. NaOH. Moles of (og (sou), available = 0.115M X 0.075L = 0.008625 mol for 0.008625 mol CO2 (504), we requise = Omol. Na04 x 0.008625 mot te fsluha Imol. Co (souly = 0.05175 mol of NaOH. But we have only 0.02275 mol. Nadh available and Itence Nadt is limiting reagent. 0.02275 mol. Mooh will produce = 2 mol.co (OH)3 x 0. 02 275 molingot Mass of C0f014), will produce = moles x molar mass = 0,007583x109.96 = 0.8349 COCOH), 6 mol naolt -0.007583 mol