Question

Cobalt (II) chloride exists in two hydrated forms, the dihydrate and hexahydrate forms. A chemist grabs cobalt (II) chloride hexahydrate from the shelf and wants to dehydrate the salt in the same manner you used in this experiment. If 5.00 g of the hexahydrate were heated to drive off waters of hydration, how many grams of the anhydrous salt would remain?

Answer 1

Colle. 6460 > Colla + 6H₂O No of moles of colle. 6H₂O= Mass - olar Mass - = 5.00g = 0.0210 mol t 237.93g mot According to Balanced Rah, 1 mole Colle. Otgo ccobelt Chlevicka bexahydrate) gives I hole Colle (Anhydrous) . No of moles of Colle = 0.0210 mol to Mass of Colly ē No of moles x Molar Mass (Anhydrous) o "= 0.0210 mal X 129.839_9Imal = 2.739