186 kmolka"), what is the The amount of 2.32 mol of a sugar is added to...

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Answer 1

Answer #1

deltaTf = Kf*m

Kf = 1.86K/molkg^-1

m = molality = moles of solute/mass of solvent in kg = 2.32mol/2.00kg= 1.16mol/kg

deltatf = 1.86K/molkg * 1.16mol/kg = 2.16C

Tf = -2.16C (decrease in freezing point)

Answer 2

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