Question

Determine whether or not the reaction indicated will occur spontaneously. 2Cu+(aq) + Ni(s) Ú 2Cu(s) + Ni2+(aq)

Answer 1

The Given Reaction:

2Cut (aq) + Ni(s) + 2Cu(s) + Ni2+ (aq)

Half cell Reaction:

Cathode

Cut(aq) + le + Cu(s)
  
ECut/Cu = 0.53V

....1

Anode

Ni(s) + Ni2+ + 2e

EN 2+/Ni = -0.25V

Ecell = ECu2+/Cu – Epi2+/Ni

= 0.53 -(-0.25) = 0.78

= 0.53 - (-0.25) = +0.78V

Here, $E_{cell}^{o}$ valve is +ve, hence the cell will be feasible and Ni will displace copper from its salt solution. In other words Nickel will reduce Copper.

And

AG = -FE

If $E^{o}$ valve is +ve the the valve of $\Delta G^{o}$ will be negative, we can say that the reaction will occur spontaneously.