Homework Answers
First we will find volume of NaOH consumed in all three trials
Trail 1 = final- initial = 22.05 ml
Trial 2 = final - initial = 18.45 ml
Trial 3 = final - Initial = 21.0- 1.05 = 19.95
So average NaOH consumed = (22.05+18.45+19.95) /3
=20.15 ml
Molarity of NaOH used = 0.210 ml
So by using formula
M1V1= M2V2
We can find molarity of HCl
Where
M1= molarity of NaOH= 0.210
V1 = volume of NaOH = 20.15 ml
M2 = molarity of HCl
V2 = volume of HCl = 25
Putting value
We get
0.210× 20.15 = M2 × 25
M2 = 0.16926 M
So molarity of HCl is 0.169 moles
I hope this helps. If you have any query or want more detailed explanation, feel free to ask in the comments section below.
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Hayden McNeil general chemistry
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