For the equilibrium 2PH3(g) ⇌ P2(g) +3H2(g), the equilibrium partial pressures are PPH3=0.049 atm, PP2=0.498 atm,...

Question

Question

For the equilibrium 2PH₃(g) ⇌ P₂(g) +3H₂(g), the equilibrium partial pressures are P_PH₃=0.049 atm, P_P₂=0.498 atm, and P_H₂=0.776 atm at 738K.

Calculate Kp.

Answer 1

Answer #1

Solution 2 PH₂, P219) + 3 H₂ (9) At equilibrium o.oug 0.498 0.776 According to low of chemical equilibrium Kp = (P2). (H2) (P

Answer 2

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