thiamine 1 OH Step A stelle For steb?.. como of yield = 50%. a mole of benzaldehyde gives since a moles . compound caj gives 212 g of te, 2x 106 g of benzaldehyde preoduct (a). . Theoretical yield = 212 g Actual yield ling) . O since, if yield a - X (0 . Theoretical yield
0.5 50- = actual yield - x ..212 g 400 . => Actual yield = = = step 2: 0.52128 106 g For 212 g. of (a) gives 20. g. of (6) But, we have 106. g. of compound (b) [as Calaceated above) : 100g of (a) gives 210 x 106 g. of (b) for = 105.9 of (6) step (2) : : % of yield = 730%. :: Actual yield = 75x1059 = 78.75 g 100 calulation of over all % yield: 2 moles of benzaldehycle gives I mole product (6) of
So Theoretical yield of (b) = 210g Actual yield of 6) = 78.759 % % of vield - . Actual yield Theoretical yield X 100 78.759 x 100 210g = 37.5% Ans . 2 'H NMR for benzaldehyde :) . C e dn. 10 ppm (s, 1H) signals, due to Ha, Hy There should be four He h Hd prestons. f: Ha, Hbf HC A 6-8 ppm . can't be 'H NMR spectra. So, (a), (bif (d) for benzalotchyde correct option : ©
Analysis of "HNMR: fi 10 ppm ( ,141) 8: 7.6 pm ( d, Hel 7.7 ppm (2,2Hb) 8 ppm ( d, a Ha) "Incorrect statement is dj because there Chiral carbon in benzoini is no 5 : (No chircel caribesi) .. Correct option : © Thiamine : T I S (a biomoleculej 2 The amine is a persistent carbene which is used ! by enzyme to catalyze benzoin condensations in vivo. (Above reaction is benzoin condens. : -ation) Correct option! Thiamine as a catalyst.. STORE STOR