Question

Calculate the amount of ZnO(s) produced during the reaction when 4410 kJ of heat were produced....

Calculate the amount of ZnO(s) produced during the reaction when 4410 kJ of heat were produced.

2 ZnS(s) + 3 O2(g) → 2 ZnO(s) + 2 SO2(g) ΔH = _ 879 kJ

Options: 10.0 mole ZnO

5.00 mole ZnO

20.0 mole ZnO

0.399 mole ZnO

0 0
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Answer #1

879 kJ of heat was released when 2 moles of ZnO was formed.

Amount of heat released for 1 mole of ZnO = 879/2

= 439.5 kJ of heat

Moles of ZnO formed = Total heat released/Heat released when 1 mole of ZnO formed

Moles of ZnO = 4410/439.5

= 10 moles

Answer = 10 mole ZnO

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