Question

Which equation is associated with the third ionization energy of aluminum?

		Al2+(g) → Al3+(g) + e-
		Al(g) + 3e- → Al3-(g)
		Al(g) → Al3+(g) + 3e-
		Al3+(g) → Al(g) + 3e-

Answer 1

Answer -

We know that,

Ionization energy is the energy needed to remove one mole electrons from one mole of atoms in the gaseous state. i.e.

X (g) + energy $\rightarrow$ X+ (g) + e-

So, For Aluminum,

Al (g) + 1st Ionization Energy $\rightarrow$ Al+ (g) + e-

Al+ (g) + 2nd Ionization Energy $\rightarrow$ Al2+ (g) + e-

Al2+ (g) + 3rd Ionization Energy $\rightarrow$ Al3+ (g) + e-

So, Al2+(g) → Al3+(g) + e- [ANSWER]