Question

Suppose 8.60 g of CH4 is allowed to burn in the presence of 16.40 g of oxygen. CH(9) +202 (9) →C02(g) + 2H20(9)
How much (in grams) O, remains after the reaction is complete? og Previous Answers Correct Part 0 How much (in grams) CO2 rem
0 0
Add a comment Improve this question Transcribed image text
Answer #1

CH4 (9) + 20208) CO2 (9) + 2H2017) No. of modes of Cty - to pigo =0.506 No. of moles of Oz = wa 16:40 = 0.512 32 Here Op is L

Add a comment
Know the answer?
Add Answer to:
Suppose 8.60 g of CH4 is allowed to burn in the presence of 16.40 g of...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Suppose 8.00 g of CH4 is allowed to burn in the presence of 15.30 g of...

    Suppose 8.00 g of CH4 is allowed to burn in the presence of 15.30 g of oxygen. CH(g) +202(g) +CO2(g) + 2H2O(9) - Part A How much (in grams) CH4 remains after the reaction is complete? 4.18 g Submit Previous Answers All attempts used; correct answer displayed Part B How much (in grams) O2 remains after the reaction is complete? og Submit Previous Answers How much (in grams) CO2 remains after the reaction is complete? 10.5 g Submit Previous Answers...

  • Suppose 8.30 g of CH4 is allowed to burn in the presence of 15.70 g of...

    Suppose 8.30 g of CH4 is allowed to burn in the presence of 15.70 g of oxygen. CH4(g) + 2O2(g) →CO2(g) + 2H2O(g) Part A How much (in grams) CH4 remains after the reaction is complete? IVO AQ R O 2 ?

  • Part A If 8.6 g of CH4 and 5.0 g of O2 react, what is the...

    Part A If 8.6 g of CH4 and 5.0 g of O2 react, what is the mass, in grams, of H2O that is produced? CH (g)+202(g)CO2(g) +2H20(g) Express your answer with the appropriate units. HA m(H2O) = Value Units Submit Request Answer

  • Part A What mass of natural gas (CH) must you burn to emit 268 kJ of...

    Part A What mass of natural gas (CH) must you burn to emit 268 kJ of heat? CH4 (g) + 202 (g) + CO2(g) + 2H2O(g) AH = -802.3 kJ Express the mass in grams to three significant figures. O AL M O O ? Submit Request Answer

  • ter 7 Question 71 - Multiple Choice Part A When 60.0 g of CH4 reacts with excess...

    ter 7 Question 71 - Multiple Choice Part A When 60.0 g of CH4 reacts with excess O2, the actual yield of CO2 is 112g. What is the percent yield? CH4 + 202 - CO2 + 2H20 O 67.9% 187% 53.6% 46.4% Submit Request Answer rovide Feedback

  • The following data were obtained for the reaction of methane with oxygen: CH4(g) + 202(g) CO2(g)...

    The following data were obtained for the reaction of methane with oxygen: CH4(g) + 202(g) CO2(g) + 2H20(1) → time(min)[CH4l (mol/L) 0 10 20 30 0.050 0.030 0.020 0.015 0.020 a) How many moles of CO2 are produced for each mole of CH4 that is used up? b) What concentration of CH4 is used up after 10 minutes? c) What is the concentration of carbon dioxide produced after 20 minutes? d) Write an equation for reaction rate in terms of...

  • (#1 continued) 16.05 g mole 44.01 g mole CH4 202-CO2 2 H:0+802.3 k 200 gmole15.02 gme...

    (#1 continued) 16.05 g mole 44.01 g mole CH4 202-CO2 2 H:0+802.3 k 200 gmole15.02 gme c. How many grams of water are produced by the complete combustion of 237.00 g of methane with 500.00 g of oxygen? d. What is the limiting reactant? e. what is the excess reactant? f. Refer back to part (c) When s used up, the reaction stops. H:O CH4 02

  • Question 1 10 points Save Answer A 0.455 g sample of magnesium is allowed to burn...

    Question 1 10 points Save Answer A 0.455 g sample of magnesium is allowed to burn in 2.315 g of oxygen gas. The sole product is magnesium oxide. After the reaction, no magnesium remains and the mass of unreacted oxygen is 2.015 g. What mass of magnesium oxide is produced?0.755 mg 0.755 g 7.55g 7.55 mg

  • For the following reaction. 16.1 grams of methane (CH) are allowed to react with 462 grams...

    For the following reaction. 16.1 grams of methane (CH) are allowed to react with 462 grams of carbon tetrachloride. CH, (g) - CC14 (9) —>2CH2C12 (9) What is the FORMULA for the limiting reagent? What is the maximum amount of dichloromethane (CH2Cl2) that can be formed? grams What amount of the excess reagent remains after the reaction is complete? grams Submit Answer R etry Entire Group 8 more group attempts remaining Previous Next

  • For the following reaction, 7.50 grams of methane (CH) are allowed to react with 25.1 grams...

    For the following reaction, 7.50 grams of methane (CH) are allowed to react with 25.1 grams of carbon tetrachloride methane (CH ) + carbon tetrachloride(g) dichloromethane (CH,CIX) What is the maximum mass of dichloromethane (CH2Cl2) that can be formed? What is the FORMULA for the limiting reagent? What mass of the excess reagent remains after the reaction is complete? gram Submit Answer Retry Entire Group 3 more group attempts remaining For the following reaction, 25.5 grams of diphosphorus pentoxide are...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT