Suppose 8.30 g of CH4 is allowed to burn in the presence of 15.70 g of...

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Suppose 8.30 g of CH4 is allowed to burn in the presence of 15.70 g of oxygen. CH4(g) + 2O2(g) →CO2(g) + 2H2O(g) Part A How m

Answer 1

Answer #1

mass of O2 = 15.70g molar mass of O2 = 3000 g/mol moles of O2 = molar mass 32.00 according to the reaction Chu (9) +202 (9) >

Comment if any problem.

Answer 2

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