Question

part B pleased

The equiibrium constant, K, for a redox reaction is read to the standard potential, B", by the equation Standard reduction potentials luk- Wheren is the number of moles of electrone transferred, F (the Faraday constant) is equal 10 28.500 c c ), the gas is equal to 8 314/walk) and is the Kamin emperature Reduction halt-reaction ( AB + + ) 0.80 c )+2 ) 0.34 397) Sula) 0.15 2H ) +202 ) D Ni+) Nia) -0.26 P. ) 23 Pela) 0.45 20) + 0.76 ALY) - 3e +A(6) 1.66 Makan) - 30 M6 -2.27 - Part A Use the table of standard reduction potentials given above to calculate the equilibrium constant at Standard temperature (25 C) for the following reaction Fe(s) - N (c)+Fe (aq) + N(6) Express your answer numerically, View Available Hints) K = 2.59x106 Previous Answers Correct When 0 and K >> 1 the reaction favors the products, - Part B Calculate the standard cell potential for the reaction X[6) + Y '( X() + Y) I K = 481x10-3 Express your answer to three significant figures and include the appropriate units. View Available Hints) Tofplate Symbol do redoresket keyboard shorious belo, Value Units "= Submit

Answer 1

X (s)+ y' (09) ->x'(aq) + 468 ) we know, doi s-WF Eeeu and . a = - RT en K .. - Rten K = -nf Eeeu - enk = nF Een When se n= no of electron transfor, Hure, nal, K = 4181x103, F = 96500 emoê', . en k = 1x soo los Feen E eu = RE en k = 8,34,32098 en (4181x103) Feeu = 0.059 log (481x15) Convert en to log Feeu = 0.059 x 6-2.3178) Feeu = -0.1367 v ] The Standard Pelu potentual = -0.1367