Question

There are two molecules with the formula C₃H₆. Propene (H₂C=CH-CH₃)is the monomer of the polymer polypropylene, which is used for indoor-outdoor carpets. Cyclopropane is used as an anesthetic.

When heated to 499 °C, cyclopropane rearranges (isomerizes) and forms propene with a rate constant of 3.57 × 10^–2 min^–1. The reaction is first order with respect to cyclopropane concentration. What fraction of the cyclopropane remains after 45 min at 499.5 °C?

Please write down the steps

Thank you

Answer 1

The Rate law for first order is given as - ln (Ac) = ket where Aos Initial concentration Az Final concentration le remaining en (A) = -83.57X10 ? x45 ka Raute constant += time en ) = -1.6065 - - 16065 J = exp(-1.6065) = 0.2 So Fraction with cyclopropane remaining after 45 minutes is 0.2 or 2. CamScanner