Question 17 4 pts What is the relationship between Kp and Kc for the reaction below? 4 NO(g) + 6 H2O(g) = 4 NH3(g) + 5 O2(g) A) K- RT RT? B) K- C) K. - (RT)K, RT D) K- OB ОА OD Ос
When determining the equilibrium concentrations for the reaction AB(g) = A(g) + B(g) Kc = [A][B] [AB] a simplifying assumption can be used under certain conditions to avoid solving a quadratic equation. Kc = [AB] – [AB] Classify each situation by whether the simplifying assumption can be used or whether the quadratic formula is required. Simplifying assumption can be used Quadratic formula required (AB) - 0.0168 M, K. = 2.26 x 10-6 (AB) = 0.154 M, K. = 2.72 x...
N2(g) + O2(g) equilibrium reaction arrow 2 NO(g); Kc = 5.6 ✕ 10−4 at 2098 K (a) What is the value of Kc for the reaction 2 NO(g) equilibrium reaction arrow N2(g) + O2(g) at the same temperature? (b) What is the value of Kc for the reaction 1/2 N2(g) + 1/2 O2(g) equilibrium reaction arrow NO(g) at the same temperature? (c) Does the equilibrium in (a) favor the reactant or the products? reactant products (d) Does the equilibrium in...
Determine Kc for A+B->C Kc=1.00x10^-2 C+B->D Kc=1.00x10^4 A + 2B -> D Kc=? Part 2: If at equilibrium D = 1.00 M, what is the concentration of A and B? Thank you.
Q(22) Kp=Kc when? A) The reaction is at equilibrium B) The reaction is exothermic C) The reaction is endothermic D) all of the gasses present are at the same temperature E) the number of moles of gas on both sides of the balanced equation is the same. Q(23) HAH +A at the equilibrium (HA) = 1.65* 10-2 M and [H") = (A-) = 5.44*10-4 M at equilibrium. Kc = A) 1.7 X 10-1 C) 1.7 X 103 D) 1.7 X...
5. If the reaction in question 4 is A(aq) + B(aq) -AB(aq) and the molarity of A in solution A is 0.60 M and the molarity of B in solution B is M, calculate the enthalpy of reaction Afrr, for the formation of 1 mole of AB in solution 6. The addition of 20.0 J of heat to a 6.00 g sample of lead at 23.0 C caused the temperature to rise to 48.7 °C. What is the specific heat...
Consider the reaction. A(aq) = 2 B(aq) Kc = 5.34 x 10-6 at 500 K If a 4.00 M sample of A is heated to 500 K, what is the concentration of B at equilibrium? [B] =
2. How is the equilibrium-constant expression (Kc) for the reaction: 2NO(a) = N2() + Ke=0.145; related to the following reaction? O2 (a) N2(a) + O2(a) = 2NO(a) K=.............. (b) 4NOQ = 2Nz () + 2O2(g) Kos......... (c) NO) 1/2 N2(0)+ 1/2O2(0) K3= +++ (d) 1/2 N2(a) + 1/2O2(a) = NO) Ke=.............. 3. Given Kc or ko for the following reactions, what is the value of Koor K? (a) l2(g) + Cl2(a) = 2ICIOX Kc = 2.0 x105 at 25°C (b)...
14.
For A+ 2B---> 2C+ D find kc if the concentration of A is 0.14M
the concentration of B is 0.17M the concentration of C is 2.0x10^-4
and the concentration of D is 3.0 x 10^-6.
17. The reaction A--> 2B+C has a Kc of 2.0 x 10^-8. If at
the begining there is only A (0.20M) use the ICE method to
determine the concentration of B at the equilibrum.
18. What is the pH for a solution that is...
1)
What is the value of Kc for the following reaction? (Calculate)
2) A reaction has an activation energy of 123 kj / mol and a K
of 0.200s ^ -1 to 311K. At what temperature will the constant be
twice that of 311k?
Fyi: “Ecuacion de” means Equation of
2C0(g) + O2(g) → 2CO2(g) CO2(g) → CO(g) + ½Oz(g) Kc = 5.0 x 1018 a 25°C Kc=??? (CALCULARLA) a 25 °C E, (1 R T X-8314 Ecuación de Arrhenius:...