Homework Answers
Solution:
| Satrting Mass of CaCO3 |
= 48.6380 g - 48.3650g = 0.273 g |
| Mass of CaCl2 obatined |
= 48.6640 g - 48.3650 g = 0.299 g |
| Mole ratio of CaCO3 to CaCl2 |
= 0.00273 mole
= 0.00269 mole Mole ratio CaCO3 to CaCl2 = 0.00273 / 0.00269 = 1.0 |
| List of possible source of error in this experiment |
|
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