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21. A sulphuric acid solution (H2SO4 : 98.09g/mol) is 5.83 M. This solution has a density of 1.329g/mL. Calculate the molalit

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Answer #1

-It 20 let 1000 ml of solution density = 1-329 g/me 1. 1000 me 1 l solution soon- moles of Haseq - moles of H2SO4 malarity =

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21. A sulphuric acid solution (H2SO4 : 98.09g/mol) is 5.83 M. This solution has a density...
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