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10. 0/10 points Previous Answers What mass of KX (Mm-120 g/mol) is required to prepare 525 mL of a pH = 12.46 solution? The pka of HX is 12.69 1.0699 x gkX Submit Answer

Answer 1

calcu ph you KX salt of weak acid & strong Base So hydrolysis for calculating - Suppose a is concenh KX kt + x of KX La a x > И, o — Их + ои an 7 1 pk = 12-6-9 2 akna kw an Klogia = 12.69 =-12.69 a ke = 10-12.69 ka = 2-05x10-13 Llo-ly 2.0sxio-13 (2.9x10- 22 a 2005X10-13 8.41 8109 tooly 2.05 PM 12.46 pon = 14-12.46 pona 1.54 a logon = 1.54 dogon = -1.54 uz You] = 10-1.54 u= [ou] = 9.9x10-2 G 2 -05*8.41 x lo 11 a = a = 17799 *10=3 1.724x102 M

a is concentration of x- so (kx) is also 1.724x102 m - Means 1.72 4X107 Mole in looo nel In love and 1. 7 4X1o-2 pole. In 525 me, 1.724 X 10-2 sol 25 Torrox Mole.= gosol x10-5 hole. Mass = Mass = Miss = Mass = Mole x Mout. gos. 1x105x120 108621x10-5 1.08 gm.