KF is conjugate base of HF
So, its pH would be more than 7
HONH3Br is conjugate acid of HONH2
So, its pH would be less than 7
C6H5NH3Cl is conjugate acid of C6H5NH2
So, its pH would be less than 7
NaCl is neutral salt.
So, its pH would be 7
C6H5NH3Cl is stronger acid as compared to HONH3Br because Kb of HONH2 is more.
So, pH of C6H5NH3Cl will be less than pH of HONH3Br
Answer:
KF: 4
HONH3Br: 2
C6H5NH3Cl: 1
NaCl: 3
Consider the following data on some weak acids and weak bases: base acid name к A...
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