Answer – We are given,
Mass of CH3OH = 29.3 g
Volume of Solution = 230 mL
We asked for a concentration in molarity. To determine the molarity we need moles and volume in L.
The moles of CH3OH –
We know the formula,
By plugging the values,
The Molarity of CH3OH –
We know the formula,
The volume in L –
We know, 1 mL= 0.001 L
So 230 mL = 0.230 L
Thus, the concentration of CH3OH in molarity is 3.98 M
you prepare a solution of CH3OH by dissolving 29.3g of CH3OH in enoigh water to make...
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