Question

i dont know if i did correct or not. other ppl answered this question with different answer .

Refer to the structure of the tetrapeptide Gly-Ala-Gly-Ala, synthesized in Part I of this experiment, to respond to Questions 5 to 7 (Figure 9.3): ili LOH Figure 9.3 Skeletal structure of the tetrapeptide prepared via solid-phase synthesis. Figure generated using ChemDraw Professional 15.1. 5. The Wang resin used in this experiment has a linker concentration of 0.72 mmol/g. Determine the mmol of linker present when 300mg of resin is used.

Answer 1

Got ace's - walls Sh. E + Ct80 x ③ we have concentration = 0.72 mmolla mmol present in 300mg = ? as you can see. Concentration mole Immol/s) mass 8 0.72 mmolla mole (meta) 1 300 mg mole- 0.72x300 mm rool 216 m m mol 216 mmo] loob mole = 0.216 mmol 6 molar mass of z no of c= 16 no of o=6 no of N = 4 no of H= 28 molar mass of c = 12.0107 molar mass of os 15.999 f/m of N = 14.0067 anos of M= 1.008 & mol

so molar mass of tetrapeptide Gly- Ala. bly. Ala : 16x12.0107 + 6x15.999+ 4 X 14.0067 + 28 X .008 372.416 g/mos molar songs = 372.42 g 1 mol (sounding off) theoretical yield mole= .216 mmol molan mass= 372042 gloos mole = mass molar mass mass= molex molar pass - 216 mmol x 872.429/mo - 80.4427 mg mass " 080443 g very close to 0.081 g -01o7g amol