Both NaOH and HCl are strong base and acid respectively. They also release one hydroxyl and hydrogen group respectively.
[OH-] = [H+]
Let x ml of HCl be required
0.4 * x = 0.8 * 50
x = 0.8 * 50/0.4 = 100ml
Therefore, 100mL of HCl would be required to neutralize NaOH.
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