Which of the following would have the greatest dipole? Why?
a) Cl—Br
b) N—F
c) O—F
d) P—S
Electronegativity of Cl = 3.16
Electronegativity of Br = 2.96
Electronegativity difference Cl-Br = 3.16 - 2.96 = 0.2
Electronegativity of N = 3.04
Electronegativity of F = 3.98
Electronegativity difference N-F = 3.98 - 3.04 = 0.94
Electronegativity of O = 3.44
Electronegativity of F = 3.98
Electronegativity difference O-F = 3.98 - 3.44 = 0.54
Electronegativity of P = 2.19
Electronegativity of S = 2.58
Electronegativity difference in P-S = 2.58 - 2.19 = 0.39
Among all, the electrinegativity difference in N-F bond is higher. If electronegaticvity difference is higher the it sould have greatest dipole.
Hence N-F would have the greatest dipole.
Option B is correct answer
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