Trying to calculate Theoretical yield but I think I need the moles of the limiting reagent. I thought I needed density if only the limiting reagent was in mL. Need help. Thanks in advance
Trying to calculate Theoretical yield but I think I need the moles of the limiting reagent....
how do i calculate the number of moles, theoretical yield, and limiting reagent on the READ ABOUT part? thank you i need help on READ ABOUT: Calculate the number of moles of 2-methyl-2-butanol and hydrochloric acid (concentrated HCl is 12 M). Based on the balanced equation, determine the limiting reagent and the theoretical yield of 2-chloride-2-methylbutane. PREPARATION AND ANALYSIS OF T-AMYL CHLORIDE ОН HCI (conc.) + H2O DISCUSSION: Compounds with good leaving groups often participate in substitution reactions. Two limiting...
6. (25 pts) (a) Calculate the theoretical yield, (b) limiting reagent, and (c) percent yield of the above reaction if you were to react 48 mmol of 1-Butanol with 60 mmol of aqueous hydrobromic acid and you obtained 4.1g of 1-Bromobutane? SHOW ALL CALCULATIONS (a) Theoretical Yield: (b) Limiting Reagent: (c) Percent Yield:
2. Calculate the limiting reagent, theoretical yield, and percent yield of the following reaction. (6 pts) NAOH / H20 2 CHз Нас 3.0 g 1.3 g 5.2 g MW: 234 g/mol MW: 58.08 g/mol MW: 106.12 g/mol
i need help calculating the theoretical yield and limiting reagent for this experiment: biodiesel production using base-catalyzed trans-esterification. assume the product is 100% methyl oleate. we used a 6:1 mole ratio of methanol in the lab instead of 3:1 given in the equation. and we used a 1% by mass catalyst load for the sodium methoxide catalyst mass of total product: 28.91 g OH o R- OH OM R + 3CH₂OH Naome 3 R40CM + catalyst R 커 (methanol) (methyl...
2. Calculate the limiting reagent, theoretical yield, and percent yield of the following reaction. (6 pts) o= NaOH/H20 5.2 g MW: 106.12 g/mol H3C CH3 1.3 g MW: 58.08 g/mol 3.0 g MW: 234 g/mol
Calculate a theoretical yield for the methyl linoleate by assuming trilinolein is the limiting reagent(135mL). trilinolein+methanol=glycerol+ methyl linoleate (C57H98O6 +3 CH3OH = C3H8O3+3 C19H34O2) You may need these <Molecular weights> Soybean oil: 872.60g/mol Glycerol: 92.10g/mol Methanol: 32.04g/mol <Densities> Soybean oil: 0.92g/mL Glycerol: 1.25g/mL Methanol: 0.79g/mL
Please find theoretical yield and limiting reagent for both reactions. Thanks! Reactions and/or chemicals of interest: HBr Rr+ 1-hexene 1-bromohexane Br 2-bromohexane Molar Mass: .llolmo Volume used: S. Volume used: 1:0 ml Concen Concentration: _ 1.8 M Density: 0.6730mL Moles: - Boiling Point: 6.3°C Since both products have the same molar mass, calculate the yield of the mixture of both products. Moles: Molar Mass: 105.07! gimur Limiting Reagent: Theoretical Yield: X + HBr - X 3,3-dimethyl-1-butene 1-bromo-3,3-dimethylbutane 2-bromo-3,3-dimethylbutane Br 2-bromo-2,3-...
2. Calculate the limiting reagent, theoretical vield. and percent yield of the following reaction. (6 pts) NaOH / H20 H + 5.2 g MW: 106.12 g/mol H3C CH3 1.3 g MW: 58.08 g/mol 3.0 g MW: 234 g/mol
please show how to find each one 2. Calculate the limiting reagent, theoretical yield, and percent yield of the following reaction. (6 pts) NaOH/ H20 2 CH3 Hас 3.0 g 1.3 g 5.2 g MW: 234 g/mol MW: 58.08 g/mol MW: 106.12 g/mol
what is my limiting reagent, theoretical yield calculated from moles , and % yield for the synthesis of banana oil? Isoamyl acetate (banana oil) is made by the acid catalyzed reaction (fischer esterification) between isoamyl alcohol and acetic acid. sulfuric acid was used as the catalyst for the fast conversion of product from starting alcohol and acid. the catalyst only affects the rate of the reaction not the extent of the reaction. here is the data from lab: here is...