Calculate a theoretical yield for the methyl linoleate by assuming trilinolein is the limiting reagent(135mL).
trilinolein+methanol=glycerol+ methyl linoleate (C57H98O6 +3 CH3OH = C3H8O3+3 C19H34O2)
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<Molecular weights>
Soybean oil: 872.60g/mol Glycerol: 92.10g/mol Methanol: 32.04g/mol
<Densities>
Soybean oil: 0.92g/mL Glycerol: 1.25g/mL Methanol: 0.79g/mL
Calculate a theoretical yield for the methyl linoleate by assuming trilinolein is the limiting reagent(135mL). trilinolein+methanol=glycerol+...
Trying to calculate Theoretical yield but I think I need the moles of the limiting reagent. I thought I needed density if only the limiting reagent was in mL. Need help. Thanks in advance Synthesized 2-chloro- Zmethyl butane starting with 10 mb of 2-chloro- 2 methyl butanol. The reaction yielded a product of 9.4312 g Calculate percent yield. Molar Mass of 2-chloro-2 methyl butanol. 10ml 122.59 g/mol C5H, CIO Molar Mass of 2-chloro-2 methyl butane 106.59 g/mol Cs Huch
i need help calculating the theoretical yield and limiting reagent for this experiment: biodiesel production using base-catalyzed trans-esterification. assume the product is 100% methyl oleate. we used a 6:1 mole ratio of methanol in the lab instead of 3:1 given in the equation. and we used a 1% by mass catalyst load for the sodium methoxide catalyst mass of total product: 28.91 g OH o R- OH OM R + 3CH₂OH Naome 3 R40CM + catalyst R 커 (methanol) (methyl...
2. Calculate the limiting reagent, theoretical yield, and percent yield of the following reaction. (6 pts) o= NaOH/H20 5.2 g MW: 106.12 g/mol H3C CH3 1.3 g MW: 58.08 g/mol 3.0 g MW: 234 g/mol
2. Calculate the limiting reagent, theoretical yield, and percent yield of the following reaction. (6 pts) NAOH / H20 2 CHз Нас 3.0 g 1.3 g 5.2 g MW: 234 g/mol MW: 58.08 g/mol MW: 106.12 g/mol
6. (25 pts) (a) Calculate the theoretical yield, (b) limiting reagent, and (c) percent yield of the above reaction if you were to react 48 mmol of 1-Butanol with 60 mmol of aqueous hydrobromic acid and you obtained 4.1g of 1-Bromobutane? SHOW ALL CALCULATIONS (a) Theoretical Yield: (b) Limiting Reagent: (c) Percent Yield:
what is my limiting reagent, theoretical yield calculated from moles , and % yield for the synthesis of banana oil? Isoamyl acetate (banana oil) is made by the acid catalyzed reaction (fischer esterification) between isoamyl alcohol and acetic acid. sulfuric acid was used as the catalyst for the fast conversion of product from starting alcohol and acid. the catalyst only affects the rate of the reaction not the extent of the reaction. here is the data from lab: here is...
2. Calculate the limiting reagent, theoretical vield. and percent yield of the following reaction. (6 pts) NaOH / H20 H + 5.2 g MW: 106.12 g/mol H3C CH3 1.3 g MW: 58.08 g/mol 3.0 g MW: 234 g/mol
Find the limiting reagent for the nitration of methyl benzoate.? Then calculate the percent yield I used Methyl benzoate - 2.3mL 15M HNO3- 3mL 18M H2SO4- 3mL Yield of crude product- 2.62g Yield of recrystalized product 1.89g
Calculate the theoretical yield I got 0.0103 mols of methyl benzoate and 0.0224 mols of nitric acid. Methyl benzoate is the limiting reactant 4. Calculate the theoretical yield (in grams) of the methyl nitrobenzoate isomer formed in the reaction from the amounts used in the procedure. Be sure and use the limiting reagent for your caleulations. Show your work and use correct number of significant figures in your answer. 5. Yield of product:
answer it all please BS132 Experiment 3 2018-2019 The limiting reagent is the reagent which will completely react and so iIs excess. It will therefore be the reagent for which a lower number o present. Compare the respective molar proportions of the reagents used A and B above] and deduce which is the limiting reagent not in f moles are Igiven by Limiting reagent = 1 mark Scale of reaction (i.e. number of moles of limiting reagent used) - mol...