Question 1: A buffer is formed by adding 2.35 g of benzoic acid, C6H5COOH, (Ka = 6.3 x 10–5) and 4.32 g of NaC6H5COO in 1 L of water. Over what range of pH values would this buffer be most effective?
Question 1: A buffer is formed by adding 2.35 g of benzoic acid, C6H5COOH, (Ka =...
Benzoic acid, C6H5COOH, is a weak acid with Ka = 6.3 × 10-5. What amount of sodium benzoate, C6H5COONa, must be dissolved in 300. mL of 0.400 M C6H5COOH, in order to prepare a buffer of pH 4.50? A. 0.24 mol B. 0.12 mol C. 0.36 mol D. 0.60 mol E. 0.48 mol
What is the pH of 0.7 mol/L benzoic acid solution? benzoic acid = (C6H5COOH, Ka = 6.6 x 10-5) A. 2.17 B. 11.8 C. 4.34 D. 9.80
Calculate the pH of a 0.496 M aqueous solution of benzoic acid (C6H5COOH, Ka = 6.3×10-5) and the equilibrium concentrations of the weak acid and its conjugate base. pH = _____ [C6H5COOH ]equilibrium = _____M [C6H5COO- ]equilibrium = _____M
What mass of benzoic acid, C6H5COOH, would you dissolve in 300.0 mL of water to produce a solution with a pH = 2.75? C6H5COOH+H2O⇌H3O++C6H5COO−Ka=6.3×10−5 Express your answer using two significant figures.
Question 2 What mass of sodium benzoate (NaC6H5COO, MM = 144. 11 g/mol) is required to create a 125. mL buffer with 1.30 M benzoic acid (C6H5COOH, Ka = 6.3* 10-5) that has a pH = 3.75? Calculate your answer in grams. Round to one decimal place and only input the number value. (Do not add a unit.)
QUESTION #1 What is the pH of a buffer by mixing 1.00L of 0.020M benzoic acid, HC,H,O2, with 3.00L of 0.060M sodium benzoate, NaC HO2? Ka for benzoic acid is 6.3 x 10-5. Write the reaction of the buffer when acid is added to the system. Write the reaction of the buffer when base is added to the system. QUESTION #1 What is the pH of a buffer by mixing 1.00L of 0.020M benzoic acid, HC,H,O2, with 3.00L of 0.060M...
Titrate 40.0 mL of 0.0350 M benzoic acid (C6H5COOH, Ka = 6.3 × 10–5) with 0.0700 M NaOH Calculate the pH in the solution at equivalent point. a) 5.716 b) 8.284 c) 8.372 d) 5.628 e) 7.546
Calculate the [benzoic acid], C6H5COOH, needed to provide a [H3O+] of 3.5 x 10-4 M. The Ka of benzoic acid is 6.3 x 10-5.
calculate the benzoic acid, C6H5COOH, needed to provide a [H3O+] of 3.5 x 10^-4 M. the Ka of benzoic acid is 6.3 x 10^-5.
A benzoic acid/potassium benzoate buffer solution has a pH = 4.25. The concentration of benzoic acid (C6H5COOH, Ka = 6.5 × 10-5) in the solution is 0.54 M. What is the concentration of potassium benzoate (KC6H5COO, Kb = 1.5 × 10-10) in this buffer solution?