Diamond will spontaneously change to graphite because: Select one: O a. it is a process that...
For a process to be spontaneous: a) b) the entropy of universe increases and Gibbs energy of the system decreases. the entropy of system decreases and Gibbs energy of the universe increases. the entropy of system increases and Gibbs energy of the universe decreases the entropy of universe decreases and Gibbs energy of the system increases. c) d)
a statement of the first law of thermodynamics is that a. in a spontaneous process, the entropy of the universe increases b. there is no disorder in a perfect crystal at 0 k. c. the total energy of the universe is constant. d. the totla energy of the universe is constant. e. mass and energy are conserved in all chemical reactions can only pick one answer i think it is E
why are the other options wrong? For a process to be spontaneous: the entropy of universe increases and Gibbs energy of the system decreases. a) the entropy of system decreases and Gibbs energy of the b) universe increases. the entropy of system increases and Gibbs energy of the universe decreases. c) of universe decreases and Gibbs energy of the d) the entropy increases system
Diamon and graphite are two crystalline forms of carbon. At 1 atm and 25°C, diamond changes to graphite so slowly that the enthalpy change of the process must be obtained indirectly. Determine delta H rxn for C(diamond) > C(graphite) with equations from the following list: Diamond and graphite are two crystalline forms of carbon. At 1 atm and 25°C, diamond changes to graphite so slowly that the enthalpy change of the process must be obtained indirectly. Determine AHxn for C(diamond)...
Enzymes are important to biology because they can be used to Select one: O a. Control when chemical reactions happen O b. Control where chemical reactions occur O c. Link different chemical reactions O d. Couple ATP hydrolysis to activity O e. All of the above Diffusion is the movement of solute propelled by collisions with water. Diffusion spontaneously transforms energy concentration gradients into energy equilibrium conditions just like any other spontaneous reaction. Select one: O a. high; high O...
Amphiphilic molecules, such as phospholipids spontaneously form micelles/vesicles in water because: a) The entropy of the detergent increases b) The enthalpy overcomes the entropy c) The entropy of water increases d) The change in free energy is positive e) When water interacts with the hydrophobic groups in the detergent, the water becomes less ordered Question 2: Which of the following reactions represent a deamination reaction? S + 2H + 2e c) H2CO3 + H20 = H30+ + HCO3 но нR...
1 out of 10 attemp Enter your ans wer in the provided box Diamond and graphite are two crystalline forms of carbon. At 1 atm and 25°C, diamond changes to graphite so slowly that the enthalpy change of the process must be obtained indirectly. DetermineA for rxn (diamond)- → C (graphite) C with equations from the following list: (1) Cdia (2) 2CO2(g)→2CO(g ) + O2(g) (3) C(graphite) +02(g)→CO2(g) (4) 2C0(g)→C(graphite) + CO2(g) AH AH-566.0 kJ AH--393.5 kJ AH--172.5kJ =-395.4 kJ...
20. Which of the following statements is FALSE? A. The entropy of the universe increases during spontaneous processes. B. During chemical and physical changes, energy is conserved. C. The entropy of H2O liquid is greater than the entropy of H2O solid at 0°C. D. The entropy of O2(g) should be greater than the entropy of CO2(g) when at the same temperature, E. The absolute entropy of a substance generally decreases when temperature decreases.
A change that takes place without the continuous input of energy is said to be Select one: O a. spontaneous O b. nonspontaneous O c. natural O d. un-natural All processes involve an increase in the entropy of the universe is a statement of the Select one: O a. 2nd law of thermodynamics O b. 1st law of thermodynamics c. 3rd law of thermodynamics O d. 4th law of thermodynamics The entropy of a perfect crystal at O K is...
1. Determine the standard Gibb's free energy change for the conversion of diamond into graphite in units of kJ/mol and is it spontaneous, nonspontaneous, or neither. Cdiamond (s) ? Cgraphite (s) f° for diamond = 2.9 kJ/mol f° for graphite = 0.0 kJ/mol (Please be careful wtih sig figs.) 2. For the following reaction, = 68.1 kJ/mol: 2 C(s) + 2 H2(g) ? C2H4(g) Determine for the reaction in units of kJ/mol at 1800. K, a partial pressure of C2H2 of...