1. Determine the standard Gibb's free energy change for the conversion of diamond into graphite in units of kJ/mol and is it spontaneous, nonspontaneous, or neither.
Cdiamond (s) ? Cgraphite (s)
f° for diamond = 2.9 kJ/mol
f° for graphite = 0.0 kJ/mol (Please be careful wtih sig figs.)
2. For the following reaction, = 68.1 kJ/mol:
2 C(s) + 2 H2(g) ? C2H4(g)
Determine for the reaction in units of kJ/mol at 1800. K, a partial pressure of C2H2 of 0.010 atm, and a partial pressure of H2 of 0.98 atm. (Please be careful wtih sig figs.)
1)
Given:
Gof(Cdiamond(s)) = 2.9 KJ/mol
Gof(Cgraphite(s)) = 0.0 KJ/mol
Balanced chemical equation is:
Cdiamond(s) ---> Cgraphite(s)
?Go rxn = 1*Gof(Cgraphite(s)) - 1*Gof( Cdiamond(s))
?Go rxn = 1*(0.0) - 1*(2.9)
?Go rxn = -2.9 KJ
Answer: -2.9 KJ
This is spontaneous because ?Go rxn is negative
Only 1 question at a time please
1)
Given:
Gof(Cdiamond(s)) = 2.9 KJ/mol
Gof(Cgraphite(s)) = 0.0 KJ/mol
Balanced chemical equation is:
Cdiamond(s) ---> Cgraphite(s)
?Go rxn = 1*Gof(Cgraphite(s)) - 1*Gof( Cdiamond(s))
?Go rxn = 1*(0.0) - 1*(2.9)
?Go rxn = -2.9 KJ
Answer: -2.9 KJ
This is spontaneous because ?Go rxn is negative
Only 1 question at a time please
1. Determine the standard Gibb's free energy change for the conversion of diamond into graphite in...
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What is the standard Gibbs energy for the transformation of diamond to graphite at 298 K? Cdiamond+Cgraphite Express your answer to three significant figures and include the appropriate units. ► View Available Hint(s)
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