Question

In Labrador retrievers, two autosomal loci interact to determine their vision types. One locus determines whether a lab can see in color (colorvision= C) and it's dominant over the allele for blindness (colorblind= c). If a lab can see color then the alleles located in the second locus will determine if the turtle's color vision also includes the ability to see neon colors (neon= N). The ability to see neon colors (N) is dominant in the inability of seeing neon colors (no neon colors= n). If two labrador retrievers that are heterozygous at both of the loci are crossed- what will be the proportion of the labs' offspring with color vision and the ability to see neon colors? In order to receive all the bonus points for this question please record the steps used.

Answer 1

C_N_ = neon colours

C_nn = no neon

ccN_ = colour blind

ccnn = colour blind

CcNn × CcNn

Gametes	CN	Cn	cN	cn
CN	CCNN neon	CCNn neon	CcNN neon	CcNn neon
Cn	CCNn neon	CCnn no neon	CcNn neon	Ccnn no neon
cN	CcNN neon	CcNn neon	ccNN blind	ccNn blind
cn	CcNn neon	Ccnn no neon	ccNn blind	ccnn blind

PR - 9 (neon) : 3 (no neon) : 4 (blind)

Proportion of progeny able to see neon colours = 3/16

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