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The figure shows two connected wires that are made

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Answer #1
Concepts and reason

The concept required to solve the problem is the drift speed.

Write the relationship between the current, the drift velocity, number of electrons per atom, electronic charge and cross-sectional area of the wire. Derive the proportionality of the drift velocity with the area of cross section of the wire. Compare the areas to calculate the drift velocity.

Fundamentals

The drift velocity of the electron through the wire is,

neA

Here, is the current, п
is the number of electrons per atom, e
is the electronic charge and A
is the area of cross section.

Area of cross section of wire is,

ла
A
4

Here, is the diameter of the wire.

Area of cross section of left wire is,

л.
A
4

Here, d
is the diameter of the left wire.

Substitute 1.0mm
for d
and 3.14rad
for . The area of cross section of left wire is,

10 m
(3.14 rad) 1.0mm1.0mm
= 7.85x107 m2

Area of cross section of right wire is,

л.
А,
4

Here, is the diameter of the right wire.

Substitute 2.0mm
for and 3.14rad
for . The area of cross section of right wire is,

103 m
(3.14 rad) (2.0mm)1.0mm
4
31.4x107 m

The ratio of cross sectional areas, 4,/A
, is.

A7.85x107m2
31.4x107 m2
1
4

The drift velocity of the electron through the left wire is,

neA,

Here, is the current through the left wire, п
is the number of electrons per atom, e
is the electronic charge.

The current through both the wires is same since the wires are connected in series. The number of electrons per atom is same for both the wires since the wires are made of same material. The electronic charge is a unique value.

The drift velocity of the electron through the left wire is,

I
dr
neA

The ratio of drift velocities, , is,

neAz
V&
dr
neA,
A2

Substitute /4
for . The ratio of drift velocity,

dr
4

The drift velocity of electron in right wire is,

dr

Ans:

The drift velocity of electron in right wire is a/4
.

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