Question

Your Name: Solutions and Dilutions 10mL added to 990mL 1mL 5mL added to 5mL 1M HCI 1ml added to 99mL 1L Total volume 100mL Total volume 1-10mL Total volume 7(6). Examine the dilution series shown above and calculate the following. Show all work for full credit IDF of A: IDF of B: IDF of C: TDF of A: TDF of B: TDF of C: 8 (1). The stock (starting) solution of HCI was 1M. What will be the concentration of Solution A after the first dilution step (1mL. into 100mL)? Show your work 9 (3). Provide detailed directions for preparing a 0.5M MgCl solution in a total volume of 1L.

Answer 1

7.

IDF of A:

1 ml of stock solution is diluted down to a total volume of 100 ml.

So, the dilution factor will be 1/100 = 10-2.

TDF of A will be the same as IDF of A as there are no preceding dilution.

IDF of B:

5 ml of dilution A is diluted down to 10 ml total volume.

So, IDF of B is 5/10 = 0.2.

Now, TDF of B will be (IDF of A) * (IDF of B) = 0.2 * 10-2.

IDF of C:

10 ml of dilution B is diluted down to total volume 1000 ml.

So, the IDF of C = 10/1000 = 1/100 = 10-2.

So, TDF of C = (IDF of A) * (IDF of B) * (IDF of C) = 0.2 * 10-2 * 10-2 = 0.2 * 10-4.

8. The stock solution concentration, V1 = 1 M.

The volume of Stoc solution added, S1 = 1 ml.

Working solution volume, V2 = 100 ml.

The concentration of the working solution, S2: ?

We know that: V1S1 = V2S2

or, 1 * 1 = 100 * S2.

or, S2 = 1/100 = 10-2.

So, The concentration of the working solution, S2: 10-2.