Homework Answers
2) recombination frequency= (number of recombinants/total
number)
100
maximum recombination frequency if the genes are not linked=50%, so if the genes are linked the recombination frequency is less than 50%, then the number of recombinant progenies is less than the number of parental type progenies, here the number of green, short and yellow tall are less than the number of green tall and yellow, short, so the answer is
recombination frequency=( ( number of green, short + number of
yellow tall)/total number of progenies)100
= ((48+46)/1566)100
= 6 %
recombination frequency in percentage is the distance between the genes in centimorgan so the distance between genes=6 cM, so genes are linked on a chromosome.
recombination frequency=6%
3) the same.
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Questions 97-98 refer to this information ln pea plants, tal () is dominant to short (e). Green seed (G) is dominant to yellow (g). These genes are located on actosomes 97. i two heterorygous tall, green seeded plants are crossed, what proportion of their offspring will be short, yelow seeded plants? a· 0/16 b 9/ e vi6 116 if a green seeded plant is crossed with a yellow plant and 6 out of 10 offspring are yellow seeded, what is...
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Hope someone can help me with this. Thanks!
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