Question

In your in-class activities two weeks ago, we asked you about a population of spruce warblers living on a remote tropical island. This week, consider a different population of spruce warblers living on a different tropical island. Like that previous week’s population, the size of these warblers’ feet is determined by one gene with two alleles: F and f. These alleles show incomplete dominance, with FF individuals having large feet, Ffhaving medium feet, and ff having small feet. You capture 100 of these birds and count the following:

15 have large feet

64 have medium feet

21 have small feet

b) Is this population in Hardy-Weinberg equilibrium? Be sure to work through the calculations and show your work.

Answer 1

The warbler population is not in Hardy- Weinberg Equilibrium as the expected numbers and observed numbers are not same.

The explanation is provided below:

Phenotype Senetype Number (observed) large feet - F - Nr=15 medium feet - ff - NF = 64 small feet - If - N = 21 Total = N = 100 QNFF + Nff Allele frequency of F =P = 2 2N (2x15) +64 - 94 =(0.47] 2x100 Allele frequency of f = 4= 2Nff that - (axal) +64 - 1096 - 10:53 200 AN 200 we know, p+9 = 1 » (Pra)² = 1 > p² + 2pq + q² = 1 (FF) (Ft) (H) Expected frequency of FF = p = (0.47)2 = 0.2209 Ff = 289 = 2X0.47 X0-53 = 0.4982 H = 72 = (0.53) - 0.2809 out of 1oo warblers, Expected number of ff = 0.2209 x100 = 22.09 ~ 22 = 0.498 2 x 100 =49.82 ł 50 H = 0.2809 x 100 = 28.09 ~28 To see whether this population is in Hardy-Weinberg Equilibrium or not, we have to calculated x value. (chi-square valere).

Phenotype obrowed (0) Expected (0) CO-E) (0-6)? large feet 15 22 -7 49 (0. 42 = 2.23 64 50 114 196 195 = 3.92 Medium fect 50 small feet 21 28 -7 49 43 = 1.25 100 100 XP-7.9 Total x² = 2.9 Total phenotypes = 3 (large, medium, small) .: Degree of freedom = 3-1=2 I at 0.05, op=5.99; at 0.01 ) P value = aneby <PL 0.05 P=9.21; this data is taken from chi-square probability conclusion Chart 0.01 Pvalue is less than 0.05 . so, the null hypothesis of H-W equilibrium is rejected. This means the deviation of expected beerved ealue is considered significant to reject null hypothesis. cocco . The population is not in Hardy-Weinberg Equilibrium as the expected and obserleed numbers are very much different.