Question

5. Fur colour in mice is a single gene trait controled by two alleles. In a population of 75 mice, 21 are homozygous dominant
3. In garden pea plants, the yellow seed colour (n is dominant over the In a population of 24 pea plants, 15 pea plants are h
Match the following terms with their correct definitions listed below 1. Definitions Terms Gene pool A group of individuals f
5. Fur colour in mice is a single gene trait controled by two alleles. In a population of 75 mice, 21 are homozygous dominant, 37 are heterozygous dominant, and 17 are homozygous recessive. What is the frequency of the dominant allele in the population? Show all work and record your answer as a value between O and 1 rounded to two decimal places 6. The Hardy-Weinberg principle states that allele and genotype frequencies remain constant from one generation to the next, as long as specific conditions are met. 2 Write Yes or No for the conditions that must be met from the provided statements. Mutations are exponentially occurring. All members of the population breed. Everyone produces the same number of offspring. The population is infinitely large. There is no migration in or out of the population. Nonet mutations are occurring. Natural selection of beneficial traits is occurring. Natural selection is not occurring. All mating is completely random. Offspring are able to migrate out of the population
3. In garden pea plants, the yellow seed colour (n is dominant over the In a population of 24 pea plants, 15 pea plants are homozygous d heterozygous dominant, and 3 are recessive. seed colour . dominant, 6 are Show all work and record your response Find the frequency of the following. significant digits. using three b. Yy genotype:_ yy genotype: C. In fruit flies, long wings (L) are dominant over short wings 4. の. In a population of 45 fruit flies, 27 have LL genotypes, 13 have LI genotypes, and 5 havelI genotypes. Find the frequency of the following. Show all work and record your answer as a value between 0 and 1 rounded to two decimal places. long-winged fruit flies: a. b. short-winged fruit flies:
Match the following terms with their correct definitions listed below 1. Definitions Terms Gene pool A group of individuals from the same species living in the same region at the same time A. Genes A population that maintains its allele frequencies by meeting the five given conditions B. Alleles Hardy-Weinberg Equilibrium C. The genetic composition of a given population Microevolution Different forms of the same gene D. Population E. A gradual change in the allele frequencies F DNA that code for specific proteins Choose the correct frequency for the following statements. 2. Frequency Statement Asample of a mouse population has a frequency of 0.18 for the dominant allele for black hair coat (B). A. Allele frequency B. Genotype frequency C. Phenotype frequency Asample of a mouse population has a frequency of 0.32 for heterozygote coat colour individuals (Bb). A sample of a mouse population has a frequency of 0.48 for white coat colour individuals.
0 0
Add a comment Improve this question Transcribed image text
Answer #1

5.

Total no. Of progeny = 75

No. Of homozygous dominant = 21

No. Of heterozygous dominant = 37

No. Of homozygous recessive = 17

Genotypic frequency of homozygous dominant = 21/75 = 0.28

Allelic frequency of dominant allele = √0.28 = 0.529

Genotypic frequency of homozygous recessive = 17/75 = 0.226

Allelic frequency of recessive allele = 0.475

6.

As per HWE, a population should be non evolving, no evolutionary force must act on the population.

◆ no mutation

◆ no migration

◆ random mating

◆ large population

◆ no selection

◆ large breeding population

3. Total pea plants = 24

Homozygous dominant = 15

Heterozygous dominant = 6

Homozygous recessive = 3

Genotypic frequency of homozygous dominant = 15/24 = 0.625

Allelic frequency of dominant allele = √0.625 = 0.791

Genotypic frequency of homozygous recessive = 3/24 = 0.125

Allelic frequency of recessive allele = √0.125 = 0.354

Genotypic frequency of heterozygous dominant = 6/24 = 0.25

4. Total fruit flies = 45

Long winged fruit flies = LL + Ll = 27 + 13 = 40

Genotypic frequency of long winged fruit flies = 40/45 = 0.889

Short winged fruit flies = ll = 5

Genotypic frequency of short winged fruit flies = 5/45 = 0.112

If you find the answer useful then please hit the like button.

Add a comment
Know the answer?
Add Answer to:
5. Fur colour in mice is a single gene trait controled by two alleles. In a population of 75 mice, 21 are homozyg...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • 1.)If the population frequencies of two alleles at a locus are B = 0.5 and b...

    1.)If the population frequencies of two alleles at a locus are B = 0.5 and b = 0.5, what is onepossible set of frequencies for the three resulting genotypes that would NOT reflect Hardy- Weinberg equilibrium? 2.)In a population that is in Hardy-Weinberg equilibrium, the frequency of the homozygous recessive genotype is 0.09. What is the frequency of individuals that are homozygous for the dominant allele? 3.)In humans, Rh-positive individuals have the Rh antigen on their red blood cells, while...

  • Consider a locus of interest that has two alleles: A and a. A diploid individual carrying...

    Consider a locus of interest that has two alleles: A and a. A diploid individual carrying these alleles can have one of three genotypes: AA, Aa, or aa; a population will consist of some combination of AA, Aa, and aa individuals. The relatively frequency of each of these genotypes makes up the population's structure. Hardy and Weinberg independently figured out that, in the absence of forces that cause evolutionary change, the population structure will 'settle' or default to equilibrium values,...

  • The Hardy-Weinberg principle and its equations predict that frequencies of alleles and genotypes remain constant from generation to generation in populations that are not evolving

    .1. The Hardy-Weinberg principle and its equations predict that frequencies of alleles and genotypes remain constant from generation to generation in populations that are not evolving. What five conditions does this prediction assume to be true about such a population? a._______  b._______  c._______  d._______  e._______  2. Before beginning the activity, answer the following general Hardy-Weinberg problems for practice (assume that the population is at Hardy-Weinberg equilibrium).a. If the frequency of a recessive allele is 0.3, what is the frequency of the dominant...

  • 1. A particular gene in a given population of individuals has two alleles, A and a....

    1. A particular gene in a given population of individuals has two alleles, A and a. The frequency of the A allele equals the frequency of the a allele. What are the expected genotype frequencies, assuming the population is in Hardy-Weinberg equilibrium? AA = 0.5, aa = 0.5 AA = 0.25, Aa = 0.50, aa = 0.25 O A = 0.5, a = 0.5 The answer cannot be determined because the allele frequencies are not provided.

  • 2. Alleles D and L are codominant alleles that define fur color in Madagascar lemurs. Lemurs...

    2. Alleles D and L are codominant alleles that define fur color in Madagascar lemurs. Lemurs that are homozygous for allele D (genotype DD) have dark brown fur. Lemurs that are homozygous for the L allele (genotype LL) have very light brown fur. The DL heterozygotes are generally light brown, but they have a dark patch or a collar around their neck. Among the 600 Lemurs that you studied on Madagascar, the distribution of genotypes was as follows: Dark brown...

  • 1. Fixation of Dominant Alleles Start with a population that has a gene with two alleles (A and a...

    1. Fixation of Dominant Alleles Start with a population that has a gene with two alleles (A and a) with classical Mendelian dominance that are at equal frequency (p0.5. q 0.5). Assume this first generation is at hardy Weinberg equilibrium. Calculate the genotype frequencies AA- a. Aa b. Now assume some environmental change that makes the recessive phenotype completely unfit (fitness- 0). Calculate the allele frequencies and genotype frequencies in the second generation. (Hint: Your calculations might be easier if...

  • A population of flour beetles has 1000 individuals. Normally the beetles are red in color; however,...

    A population of flour beetles has 1000 individuals. Normally the beetles are red in color; however, this population has a utation in the gene for body color that results in black beetles that are designated by the rr genotype. Red body color is dominant to black so the genotypes RR and Rr result in red beetles. Assume the population is in Hardy-Weinberg equilibrium, with a 50% frequency of each allele for body color. A) --- what is the frequency of...

  • Fictional scenario: Individuals with green hair have the presence of the dominant gene "Z" and people...

    Fictional scenario: Individuals with green hair have the presence of the dominant gene "Z" and people with purple hair are homozygous for the recessive allele “z”. There were 200 students in a classroom who were surveyed for their hair color and 155 people had green hair whereas 45 people had purple hair. Use the information to answer the next set of questions. Show your work for credit. 1) What are the variables for a recessive allele? A dominant allele? Homozygous...

  • The occurrence of the NN blood group genotype in the US population is 1 in 400,...

    The occurrence of the NN blood group genotype in the US population is 1 in 400, consider NN as the homozygous recessive genotype in this population. You sample 1,000 individuals from a large population for the MN blood group, which can easily be measured since co-dominance is involved (i.e., you can detect the heterozygotes). They are typed accordingly: BLOOD TYPE GENOTYPE NUMBER OF INDIVIDUALS RESULTING FREQUENCY M MM 490 0.49 MN MN 420 0.42 N NN 90 0.09 Using the...

  • 2.3 Problem 3 The Hardy-Weinberg equation is useful for predicting the percent of a hu- man...

    2.3 Problem 3 The Hardy-Weinberg equation is useful for predicting the percent of a hu- man population that may be heterozygous carriers of recessive alleles for certain genetic diseases. Phenylketonuria (PKU) is a human metabolic dis- order that results in mental retardation if it is untreated in infancy. In the United States, one out of approximately 10.000 babies is born with the disor- der. Approximately what percent of the population are heterozygous carriers of the recessive PKU allele? If you...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT