Question

A cross is set up: Aa Bbce X AA Bb Cc. What percentage of progeny will be heterozygous at every locus?

Answer 1

so the cross is Aa Bb cc x AA Bb Cc

so the punnet square will be

	ABc	Abc	aBc	abc
ABC	AA BB Cc	AA Bb Cc	Aa BB Cc	Aa Bb Cc
ABc	AA BB cc	AA Bb cc	Aa BB cc	Aa Bb cc
AbC	AA Bb Cc	AA bb Cc	Aa Bb Cc	Aa bb Cc
Abc	AA Bb cc	AA bb cc	Aa Bb cc	Aa bb cc

so out 16 progenies 2 will be of genotype Aa Bb Cc ( heterozygous at every locus).

so percentage = (2/16) x 100

-= (1/8) x 100

= 0.125 x 100

= 12.5 %

so 12.5% progenies will be completely hetrozygous at every loci