Question

In the stress state shown in the element in the following figure, determine the maximum principal stress (a), the angle prin in which the element must be oriented so that the maximum principal stress, the maximum shear stress (max,z) and angle max
in which the element must be oriented so that the maximum shear stress is present.

Answer 1

Batals from problem О Jx = 10ompa Ty = compa 50 mpa Enya Principal stress J;2= : ( *** 123) + (62)*+73, (626 2 51,2= 100+ Go AI + 50२ 2 80 t 400 + 2500 so h 53.8511 J ण so +53-851 133.8516 mpa Pi maximum principal stress

Tay tan 2 o principal con-dy)/2 Goo -60)/2 tan ao 2.5 principal tant (205) 28 puna 68. 1985 2 o princiando Opincipal - 34.0992 Angle of maximum principal stress

Tmax JA - Oy)2 +tang ( 100 - 60 ) ² 2 Tmax = + 50² 400 t 2500 Tmax 53.8516 mpa tan 2 Og mat con- Jy)/2 Emy -(100- 60)/2 50 tana Osmax = -0.4 2 Osmaxa tant! (-0.4) 2 Osman 2 으 - 21.soly GOG Negaets ve sign อ 8 'S ma x -10.9 000 indicates Counter clockwise diretton Result Ja 133.8516 mpa Oprin = 34. 0992 ° 53.85 16 mpa Omax -10.9007 Tmana =