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. Consider the element shown. Determine the state of stress with respect to an element oriented 22.5° CCW with respect to the
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Solution.- 1X3 Txj- 56o kPa 6x= 2100 Κρα. 67= 300 kpa 69-300 kpa 2. 22.5., ccw means positive angle 6x, 2100 + 300 2. I 00-30principle se sses 2 2. 2100 + 300 2 61 21 00-300 - 5602 2. 6! = 1200 + 1060-2260 Кра 62 6x 6y 6x-6y 2 210 3oo\ r-5 60)2 2. 22,000 TMax shear 1,060 1,600 1,200 800 (2,100, 560.0) (2,100, 560.0) Min prin 140,400 (1200,0.0) 3,000-2000 10 1000 20 0 4,00

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