Question

genetics problem:

5. On a small island, 235 mating individuals are all homozygous for brown eyes. An epidemic wipes out all but 10 young women, 2 young men, and two elderly women (both >70 years old). A boatload of foreigners arrives; the foreign population consists of six heterozygous brown-eyed young women, four homozygous brown-eyed young men, and 10 blue-eyed young men. Assuming that eye color is controlled by a single locus with the brown allele being dominant (blatantly incorrect, but assume it is so), that mating is random with respect to eye color, and that each male and each female that is capable of breeding does so, calculate the allelic frequencies of their offspring.

Answer 1

Answer :)

After the wipeout, the new population:

The population size is 14 and all are homozygous brown and therefore, genotype frequency and allele frequency are 1.

The foreign population:

Homozygous brown eyes = 4

Heterozygous brown eyes = 6

Homozygous blue eyes = 10

Total population = 20

Genotype frequency of Homozygous brown, aa = 4/20

Genotype frequency of Homozygous brown, aa = 0.2

Genotype frequency of Heterozygous brown, 2ab = 6/10

Genotype frequency of Heterozygous brown, 2ab= 0.6

Genotype frequency of Heterozygous brown, ab= 0.6/2

Genotype frequency of Heterozygous brown, ab= 0.3

Genotype frequency of Homozygous blue, bb = 10/20

Genotype frequency of Homozygous blue, bb = 0.5

Allele frequency of brown, a = √0.2

Allele frequency of brown, a = 0.45

Allele frequency of blue, b = √0.5

Allele frequency of brown, b = 0.7

In the next generation, after mating, the frequency of genotype aa = 1 x 0.45

In the next generation, after mating, the frequency of genotype aa = 0.45

In the next generation, after mating, the frequency of genotype bb = 1 x 0.7

In the next generation, after mating, the frequency of genotype bb = 0.7

Allele frequency in the next generation, a = √0.45

Allele frequency in the next generation, a = 0.67

Allele frequency in the next generation, b = √0.7

Allele frequency in the next generation, b = 0.84

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