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An electron travels with speed 0.70×107m/s between the two parallel charged plates shown in the figure(Figure...

An electron travels with speed 0.70×107m/s between the two parallel charged plates shown in the figure(Figure 1) . The plates are separated by 1.0 cm and are charged by a 200 V battery. What magnetic field strength will allow the electron to pass between the plates without being deflected?


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Answer #1

apply Electric field E = V/d

E = 200/0.01

E = 2e 4 V/m

now the relation between EF anf magnetic field B is E = Bv

B = E/v

B = 2e4/(0.7 e7)

B = 2.85 mT

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