An electron travels with speed 0.70×107m/s between the two parallel charged plates shown in the figure(Figure...
An electron travels with speed 0.70×107m/s between the two parallel charged plates shown in the figure(Figure 1) . The plates are separated by 1.0 cm and are charged by a 200 V battery. What magnetic field strength will allow the electron to pass between the plates without being deflected?
Homework Answers
apply Electric field E = V/d
E = 200/0.01
E = 2e 4 V/m
now the relation between EF anf magnetic field B is E = Bv
B = E/v
B = 2e4/(0.7 e7)
B = 2.85 mT
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