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4. in population 2 generation 2, 64 individual display the recessive trait out of 400 individuals. Is the pop in HWE? 5. Hypo
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4. For a population to be in HWE it should follow the equation p + q = 1.

P = allelic frequency of dominant phenotype

q = allelic frequency of recessive genotype

So , q = √ 64/400 = 0.4

So frequency of p = 0.6 . & # of individual with dominant genotype = p2 × 400 = 0.6×0.6 × 400 = 144

Individuals with heterozygous phenotype = 2pq × 400 = 192

P​​​​​​2 + q​​​​​​2 + 2pq = 1

.36 + 0.16 + 0.48 = 1 ( so population is in HWE) .

5. p + q + r = 1 ( allelic frequency )

p​​​​​​2 + q​​​​​​2 + r​​​​​​2 + 2pq + 2pr + 2qr = 1 ( genotypic frequency) .

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