Question

7) In Labrador retrievers, 2 independently assorting genes interact to generate coat color (B, b and E, e). The genotype B_E_ results in black coat; bbE_ results in chocolate coats; B_ee results in yellow coat; and bbee results in yellow coat. If you were a breeder, you might be especially interested in producing black and brown labs, since they might fetch the most money when sold. What proportion of these two phenotypes would you expect from the following crosses? a) BbEe x bbee b) BbEe x BbEe c) Two yellow labs (both of whom had 2 brown lab parents) d) Two brown labs (both of whom had one yellow lab parent)

Answer 1

Black = B-E- Chocolate = bbE - elio - В- ее Бbe 1) ВЬЕ, x Бb се Тbe BE Bb Ee Black @bее «шид 3) bbee X obce ол Б6 се ко (of. bbee Choco be | Бbe еlод 18 | БЬ ЕЕ X bbЕг b6EE 2 choco bbee] Тю. ВЬЕ ХВЬ Ее ав – Е. = Black 3 B-ee = yelloo 3b6E - - Сла. I obec= yellow qə3*4

Please rate high.