Question

The current in the circuit shown in the figure below equals 65.0% of the peak current at t = 6.00 ms. what is the lowest source frequency that gives this current? Hz sin 2πThe current in the circuit shown in the figure below equals 65.0% of the peak current at t = 6.00 ms. What is the lowest source frequency that gives this current?

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Answer #1

Since the circuit contains only resistor, voltahe and current will be in the same phase and the current in the circuit is, 065- sin2f(6x10) 2f(6x10 s)-sin (065) 2Tf(6x10 s)- 0.707 rad Thus, minimum frequency is, f-18.7 Hz

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