Question

Question 25 4 points Save This pedigree (Pedigree #2) illustrates the inheritance of a simple Mendelian trait. If individual II-4 marries a woman who is M. what are the chances that they would have a child with this disorder? To A 1004 B.0% C.25% 0.75 E SOM

Answer 1

ANSWER

(E) 50%

Because a person affected by an autosomal dominant disorder has 50% chance of passing the mutated gene to each child.The chance that a chid will not inherit the mutated gene is also 50% However ,in some cases an autosomal dominant disorder result from a new mutation that occurs during the formation of egg or sperm cells or early in embryonic development. In these cases, the childs parents are unaffected ,but the child may pass on the condition to his or her own children.

Most frequent instance: Aa x AA ( marriage of an affected individual HEZ with a normal individual).

--> Gamètes Imréquence) 11/21 (1/2) Aa 11/21 AA (1/2) <-- Genotype - descent ſequency (a) (A) <-- Phenotype - descent Affected Normal