Question

In a wild-type carnivorous plant, protein X is encoded by a haplosufficient gene “X”. The X...

In a wild-type carnivorous plant, protein X is encoded by a haplosufficient gene “X”.

The X protein normally homodimerizes.

The X-X dimer enzymatically catalyzes a biochemical reaction that is critical for the digestion of insects that it traps.

XD represents a dominant negative allele, a mutation, of gene X.

What would be the predicted phenotype of a plant with the genotype X+/XD ?

Which one of these pieces of information allows you to reach that conclusion?

a.

The plant would be mutant and would not digest bugs, because absolutely no X-X dimers will form in the heterozygote.

b.

The plant would be mutant and incapable of digesting insects, because X is known to be haplosufficient.

c.

The plant would be wild type and would be quite capable of bug digestion, because XD is a negative allele.

d.

The plant would be wild type and would produce the enzyme for digestions of insects, as X is haplosufficient.

e.

The plant would be mutant and would be incapable of digesting insects, as the mutant allele XD is a dominant allele.

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Answer #1

Ans- Option b is correct- the plant would be mutant and incapable of digesting insects, because X is known to be haplosufficient.

Explanation- Firstly, the plant is mutant because XD gene is present, that is mutant and secondly, it would be unable to digest insects because the gene X is haplosufficient.

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