Homework Answers
The answer is-Protein X is NFAT.The mutation is in the calcineurin phosphate domain and makes it non-functional.
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What is protein X and what gene could be mutated to cause these results? Wild type...
In a wild-type carnivorous plant, protein X is encoded by a haplosufficient gene “X”. The X...
In a wild-type carnivorous plant, protein X is encoded by a haplosufficient gene “X”. The X protein normally homodimerizes. The X-X dimer enzymatically catalyzes a biochemical reaction that is critical for the digestion of insects that it traps. XD represents a dominant negative allele, a mutation, of gene X. What would be the predicted phenotype of a plant with the genotype X+/XD ? Which one of these pieces of information allows you to reach that conclusion? a. The plant would...
Please answer 2-5 2. Consider a gene with a particular function. Mutation X and mutation Y...
Please answer 2-5
2. Consider a gene with a particular function. Mutation X and mutation Y cach cause defects in the function of the encoded protein, yet a gene containing both mutations X and Y encodes a protein that works even better than the original protein. The odds are exceedingly small that a single mutational event will generate both mutations X and Y. Explain a simple way that an organism with a mutant gene containing both mutations X and Y...
In-Class Activity #12, Protein Tratlicking Worksheet 1. You are interested in four different proteins in a...
In-Class Activity #12, Protein Tratlicking Worksheet 1. You are interested in four different proteins in a yeast cell: • protein 1 is a cytosolic protein protein 2 is a secreted protein • protein 3 is a nuclear protein protein 4 is a cell surface membrane protein with N-terminal end in extra-cellular space. a. You plan to study how the proteins are localized to their specific destination by creating the following mutations in the genes encoding proteins 1-4. Indicate how the...
For Questions 4-18, consider the mutations described in the left-hand column below. Identify whether the Lac operon will be ON or OFF in each of the environments listed across the top. The expression...
For Questions 4-18, consider the mutations described in the left-hand column below. Identify whether the Lac operon will be ON or OFF in each of the environments listed across the top. The expression of the normal (wild type) operon is given. Note that "ON" and "OFF" refer to whether the operon is expressed at high levels (ON) or basal//low/no levels (OFF). (Hint: mutations render the indicated site inactive while leaving the remaining part of the operon or protein functional.) Note...
5. Consider the wild-type F8 gene. What would happen to the 1) transcript (mRNA) sequence and...
5. Consider the wild-type F8 gene. What would happen to the 1)
transcript
(mRNA) sequence and quantity, 2) to the protein (sequence,
quantity, function) and 3) the person’s
overall phenotype if they were homozygous (both copies of the
gene are the same) for a 3 base-pair
deletion in the:
i. First intron
ii. First exon
iii. The promoter
iv. 5’UTR
v. Last exon
6. What environmental factor could affect the phenotype caused
by an F8 null mutation?
Thrombophilia is a...
32. Study the signaling pathway illustrated below, which involves two different receptors. Assume that a protein...
32. Study the signaling pathway illustrated below, which involves two different receptors. Assume that a protein is active only when it is activated, but not inhibited, by its upstream signaling molecules. Activation and inhibition are indicated by normal and blunt arrows, respectively. Assume that the transcription regulator can be activated by either the binding protein or the kinase that are immediately upstream of the transcription factor. Under which of the following conditions will the expression of target:gene "X" be induced?...
Question 36 1 pts 36. You have a population of mammalian cells growing in media containing...
Question 36 1 pts 36. You have a population of mammalian cells growing in media containing enough growth factors. Which of the following graphs corresponds to these cells when their DNA content is analyzed 24 hours after they are induced to express high levels of a mutant form of Rb protein that cannot be phosphorylated? (Note: this cell line has its cell cycle around 22 hours) Control cells #1 #2 #3 #4 #5 #6 Cell number JAN ul. 2 2...
can someone explain how to answer this with reasons why 30-45 mins after estrogen addition: Acchyiase...
can someone explain how to answer this with reasons why
30-45 mins after estrogen addition: Acchyiase (HAT, odde auhye 60-90 mins after estrogen addition: Reauitment ef Poy to open 7. T identify the Gene X DNA element responsible for regulation by a Growth Fagor, you perform a linker scanning experiment in which you mutate 10 bp Tegions centered around positions -205 to-5 in the Gene X promoter/promoter- proximal region (wt wild-type promoter). The promoter variants were tested for their ability...
Hagrid has purified a protein from unicom sweat and called UNI-1. He has then doned the...
Hagrid has purified a protein from unicom sweat and called UNI-1. He has then doned the Unit gone and inserted in rat zygotes (by microinjection) a recombinant construct containing the Uni-1 coding sequence its entire 5 UTR region, covering both the minimal promoter and a series of cutative regulatory als elements. The mutantrats develop glorious, luminous hair. Hagrid has also discovered that the UNI-1 protein binds very tightly to DNA and hypothesizes it is a transcription factor that regulates proliferation...
n 13 You have found a mutant that has a G-protein that can only bind GDP...
n 13 You have found a mutant that has a G-protein that can only bind GDP and cannot bind GTP. Which of the following might you expect in the mutant cells? red ed out of ag question Select one: a. The secondary messenger would be made constantly. b. The cells would have more energy availability due to higher GTP binding. c. The secondary messenger would not be made. O d. The primary messenger would not be able to bind to...
Please answer 2-5
2. Consider a gene with a particular function. Mutation X and mutation Y cach cause defects in the function of the encoded protein, yet a gene containing both mutations X and Y encodes a protein that works even better than the original protein. The odds are exceedingly small that a single mutational event will generate both mutations X and Y. Explain a simple way that an organism with a mutant gene containing both mutations X and Y...
In-Class Activity #12, Protein Tratlicking Worksheet 1. You are interested in four different proteins in a yeast cell: • protein 1 is a cytosolic protein protein 2 is a secreted protein • protein 3 is a nuclear protein protein 4 is a cell surface membrane protein with N-terminal end in extra-cellular space. a. You plan to study how the proteins are localized to their specific destination by creating the following mutations in the genes encoding proteins 1-4. Indicate how the...
For Questions 4-18, consider the mutations described in the left-hand column below. Identify whether the Lac operon will be ON or OFF in each of the environments listed across the top. The expression of the normal (wild type) operon is given. Note that "ON" and "OFF" refer to whether the operon is expressed at high levels (ON) or basal//low/no levels (OFF). (Hint: mutations render the indicated site inactive while leaving the remaining part of the operon or protein functional.) Note...
5. Consider the wild-type F8 gene. What would happen to the 1)
transcript
(mRNA) sequence and quantity, 2) to the protein (sequence,
quantity, function) and 3) the person’s
overall phenotype if they were homozygous (both copies of the
gene are the same) for a 3 base-pair
deletion in the:
i. First intron
ii. First exon
iii. The promoter
iv. 5’UTR
v. Last exon
6. What environmental factor could affect the phenotype caused
by an F8 null mutation?
Thrombophilia is a...
32. Study the signaling pathway illustrated below, which involves two different receptors. Assume that a protein is active only when it is activated, but not inhibited, by its upstream signaling molecules. Activation and inhibition are indicated by normal and blunt arrows, respectively. Assume that the transcription regulator can be activated by either the binding protein or the kinase that are immediately upstream of the transcription factor. Under which of the following conditions will the expression of target:gene "X" be induced?...
Question 36 1 pts 36. You have a population of mammalian cells growing in media containing enough growth factors. Which of the following graphs corresponds to these cells when their DNA content is analyzed 24 hours after they are induced to express high levels of a mutant form of Rb protein that cannot be phosphorylated? (Note: this cell line has its cell cycle around 22 hours) Control cells #1 #2 #3 #4 #5 #6 Cell number JAN ul. 2 2...
can someone explain how to answer this with reasons why
30-45 mins after estrogen addition: Acchyiase (HAT, odde auhye 60-90 mins after estrogen addition: Reauitment ef Poy to open 7. T identify the Gene X DNA element responsible for regulation by a Growth Fagor, you perform a linker scanning experiment in which you mutate 10 bp Tegions centered around positions -205 to-5 in the Gene X promoter/promoter- proximal region (wt wild-type promoter). The promoter variants were tested for their ability...
Hagrid has purified a protein from unicom sweat and called UNI-1. He has then doned the Unit gone and inserted in rat zygotes (by microinjection) a recombinant construct containing the Uni-1 coding sequence its entire 5 UTR region, covering both the minimal promoter and a series of cutative regulatory als elements. The mutantrats develop glorious, luminous hair. Hagrid has also discovered that the UNI-1 protein binds very tightly to DNA and hypothesizes it is a transcription factor that regulates proliferation...
n 13 You have found a mutant that has a G-protein that can only bind GDP and cannot bind GTP. Which of the following might you expect in the mutant cells? red ed out of ag question Select one: a. The secondary messenger would be made constantly. b. The cells would have more energy availability due to higher GTP binding. c. The secondary messenger would not be made. O d. The primary messenger would not be able to bind to...
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