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10. In a wild-type diploid fungus, protein E (encoded by the haplosufficient gene “E”) normally homodimerizes, and the E-E d

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10) dominant-negative alleles produce the ED enzyme which can inhibit the function of the E enzyme, E-ED dimer is not functional, ED-ED dimer is also not functional.

E allele is haplosufficient, means in the presence of E allele and a null allele which does not code for the functional enzyme, one E allele can produce wildtype phenotype.

but the presence of dominant-negative allele reduces the amount of functional dimer of the enzyme, E dimerizes with ED also so the phenotype is mutant because 50% of the E-E dimer compared to the wildtype cannot be produced in the heterozygotes with one dominant-negative allele and one normal allele.

so the answer is C) mutant ( no pigment production), as the mutant allele ED is dominant.

11) the F1 progeny of black and white parents are gray that is progeny shows intermediate phenotype compared to both parents, this is an example of incomplete dominant.

if one allele was dominant the F1 would have shown that dominant phenotype.

D) black and white are incompletely dominant.

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